{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 0 0 128 128 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Output" -1 11 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 3 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 10 "restart:\n " }{TEXT -1 17 "Mischungsaufgaben" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 " " 0 "" {TEXT -1 100 " Typ 1\n V1 Liter p %-ige Salzl \366sung + V2 Liter Wasser = x %-ige Mischung" }}{PARA 0 "" 0 "" {TEXT -1 30 " " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 49 " V1:=3:\n p:=0.7:\n V2:=4:\n Anteil_x:=p* V1/(V1+V2);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%)Anteil_xG$\"+++++I!# 5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 105 " Typ 2\n V Liter p1 %-ige Salzl\366su ng + x Liter Wasser = p2 %-ige Salzl\366sung ." }} {PARA 0 "" 0 "" {TEXT -1 18 " " }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 65 " V:=3:\n p1:=0.80:\n p2:=0.30:\n Liter_x:=solv e(p1*V/(V+x)=p2,x); \n" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%(Liter_xG $\"\"&\"\"!" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 115 " Typ 3\n \+ V1 Liter p1 %-ige Salzl\366sung + V2 Liter p2 %-ige Sa lzl\366sung = x %-ige Mischung " }}{PARA 0 "" 0 "" {TEXT -1 23 " \+ " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 73 " V 1:=5:\n p1:=0.4:\n V2:=8:\n p2:=0.60: \n Anteil_x:=(p1*V1+p2*V2)/(V1+ V2); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%)Anteil_xG$\"+J#p2B&!#5" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 120 " Typ 4\n x Liter p1 %-ige Salzl\366sung + V2 Liter p2 %-ige Salzl\366sung = p3 %-ige Salzl\366s ung." }}{PARA 0 "" 0 "" {TEXT -1 18 " " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 85 " p1:=0.3:\n V2:=5:\n p2:=0.15:\n p3 :=0.2: \n Liter_x:=solve( (p1*x+p2*V2)/(V2+x)=p3,x);\n" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#>%(Liter_xG$\"+++++D!\"*" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 140 " \+ Typ5\n V1 Liter p1 %-ige Salzl\366sung + V2 Liter \+ x %-ige Salzl\366sung = V1+V2 Liter p3 %-ige Salzl\366 sung." }}{PARA 0 "" 0 "" {TEXT -1 18 " " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 94 " V1:=6 p1:=800/1000:\n V2:=8:\n p3: =600/1000:\n Salzanteil_x:=solve( (p1*V1+x*V2)/(V1+V2)=p3,x);\n" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%-Salzanteil_xG#\"#>\"#S" }}}{PARA 11 "" 1 "" {TEXT -1 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }} {PARA 11 "" 1 "" {TEXT -1 0 "" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 231 " Typ 6 beach te: p1 kann auch null sein (Wasser) \n x Liter p1 %-ige Sal zl\366sung + y Liter p2 %-ige Salzl\366sung = V Liter p3 % -ige Salzl\366sung.\n Gesucht sind x und y und das Verh\344 ltnis x : y" }}{PARA 0 "" 0 "" {TEXT -1 18 " " }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 215 " p1:=20/100:\n p2:=80/100: \n V:=8:\n p3:=30/100: \n Anteil_x:=solve( (p1*x+p2*(V-x))/V=p3, x); 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